y = &x

# assume that x is stored on the stack frame at offset -8 from the base pointer
mov %rbp %rax
sub $-8 %rax


mov -8(%rbp) %rax








RAM(0xEF) = 4
rbp=0xEF
mov %rbp %rax
rax=0xEF

RAM(0xEF) = 4
rbp=0xEF
mov (%rbp) %rax
rax=4


# x = 8
# RAM(0xEF) = 4
# RAM(0xE7) = 5 # this is the location where x is allocated
# rbp=0xEF
mov -8(%rbp) %rax
# rax=5


# &x
# RAM(0xEF) = 4  # this is my base pointer rbp
# RAM(0xE7) = 5  # this is allocated to x
# rbp=0xEF
mov %rbp %rax
# rax=0xEF
sub $8 %rax
# rax=0xE7


# *y = 8;
# RAM(0xEF) = 4  # this is my base pointer rbp
# RAM(0xE7) = 5  # this is allocated to x
# rbp=0xEF
# rax=0xE7 # address of x is in y already
mov $8 (%rax)
# rax=0xE7 # address of x is in y already
# RAM(0xE7) = 8  # this is allocated to x




# x = 8
# RAM(0xEF) = 4
# RAM(0xE7) = 5 # this is the location where x is allocated
# rbp=0xEF
mov $8 -8(%rbp)
# rax=5





x = 0
if (x && printf("hello\n")) {
}